findDifference: Return the position of the first corresponding elements of a1 and a2 that are not equal

int findDifference(const string a1[], int n1, const string a2[], int n2);

Return the position of the first corresponding elements of a1 and a2 that are not equal. n1 is the number of interesting elements in a1, and n2 is the number of interesting elements in a2. If the arrays are equal up to the point where one or both runs out, return whichever value of n1 and n2 is less than or equal to the other. Here's an example:

string people[5] = { "juliet", "sierra", "samuel", "echo", "november" };
string bench[6] = { "juliet", "sierra", "charlie", "echo", "november", "samuel" };
int r = findDifference(people, 5, bench, 6);  //  returns 2
int s = findDifference(people, 2, bench, 1);  //  returns 1

Psuedocode

int findDifference(const string a1[], int n1, const string a2[], int n2){
int findDifferencePosition=-1;
for (unsigned int i=0; i<n1; i++){
//if i is less than or equal to n2
//if a1[i] is NOT equal to a2[i]
//set findDifferencePosition to i
//break
}
return findDifferencePosition;
}

Solution

int findDifference(const string a1[], int n1, const string a2[], int n2){
int findDifferencePosition=-1;
for (unsigned int i=0; i<n1; i++){
if (i <= n2){
if (a1[i]!=a2[i]){
findDifferencePosition=i;
break;
}
}
}
return findDifferencePosition;
}