findMin method: Return the position of a string in the array such that that string is <= every string in the array

Return the position of a string in the array such that that string is <= every string in the array. If there is more than one such string, return the smallest position number of such a string. Return −1 if the function should consider no elements to be part of the array. Here’s an example:

string people[5] = { "juliet", "sierra", "sierra", "echo", "november" };
int q = findMin(people, 5);  // returns 3, since  echo  is earliest
                             // in alphabetic order

Psuedocode

int findMin(const string a[], int n){
int currentMinPosition=0;
for (unsigned int i=0; i<n; i++){
//if a[i] is less than a[currentMinPosition], to check which is alphabetically before the other
//if it matches, then set currentMinPosition to i
}
return currentMinPosition;
}

Solution

int findMin(const string a[], int n){
if (n<=0){
return -1;
}
int currentMinPosition=0;
for (unsigned int i=0; i<n; i++){
if (a[i]<a[currentMinPosition]){
currentMinPosition=i;