In C++, create a method called findRun that finds the earliest occurrence in an array of one or more consecutive strings that are equal to a target string

Question

bool findRun(const string a[], int n, string target, int& begin, int& end);

Find the earliest occurrence in a of one or more consecutive strings that are equal to target; set begin to the position of the first occurrence of target, set end to the last occurrence of target in that earliest consecutive sequence, and return true. If n is negative or if no string in a is equal to target, leave begin and end unchanged and return false. Here's an example:

string d[9] = {
    "charlie", "november", "alpha", "alpha", "kilo", "kilo", "kilo", "alpha", "alpha"
};
int b;
int e;
bool b1 = findRun(d, 9, "alpha", b, e);     //  returns true and
                                          //    sets b to 2 and e to 3
bool b2 = findRun(d, 9, "november", b, e);    //  returns true and
                                          //    sets b to 1 and e to 1
bool b3 = findRun(d, 9, "sierra", b, e);  //  returns false and
                                          //    leaves b and e unchanged

Solution

bool findRun(const string a[], int n, string target, int& begin, int& end){
bool foundTarget=false;
for (unsigned int i=0; i<n; i++){
cout << a[i] << endl;